If (1-p) is a root of x^2+px+(1-p)=0, then its roots are

Question

If $(1-p)$ is a root of $x^2+px+(1-p)=0$, then its roots are

Accepted Answer

Let the other root be $\alpha$: $\alpha+(1-p)=-p \implies \alpha=-1$. Also $\alpha(1-p)=1-p \implies (\alpha-1)(1-p)=0 \implies p=1$ (since $\alpha=-1
e1$).

Roots: $-1$ and $1-p=0$.

Solutions · 1