Question 364 of 455MediumMCQ
The value of a for which the sum of the squares of the roots of x2−(a−2)x−a−1=0 assumes the least value is Solutions · 1
Official solution
α+β=a−2, αβ=−(a+1).
\[\alpha^2+\beta^2=(a-2)^2+2(a+1)=a^2-2a+6=(a-1)^2+5,\]
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