Question 331 of 455MediumMCQ
If a complex number z satisfies the equation z+2∣z+1∣+i=0, then ∣z∣ is equal to: Solutions · 1
Official solution
Let z=x+iy: real/imaginary parts give y=−1 and x+2(x+1)2+1=0. Squaring: 2[(x+1)2+1]=x2⟹x2+4x+4=0⟹x=−2.
\[z=-2-i \implies |z|=\sqrt{5}.\] Answer the question to unlock