Question 328 of 455MediumMCQ
If Z1=0 and Z2 be two complex numbers such that Z1Z2 is a purely imaginary number, then 2Z1−3Z22Z1+3Z2 is equal to: Solutions · 1
Official solution
Take Z1=1+i, Z2=1−i (so Z1Z2=−i, purely imaginary):
\[\frac{2Z_1+3Z_2}{2Z_1-3Z_2}=\frac{2-3i}{2+3i}\implies \left|\frac{2Z_1+3Z_2}{2Z_1-3Z_2}\right|=\frac{|2-3i|}{|2+3i|}=1.\] Answer the question to unlock