Question 308 of 455HardMCQ
If z is a non-real complex number, then the minimum value of (Imz)5Imz5 is: Solutions · 1
Official solution
With z=reiθ: (Imz)5Imz5=sin5θsin5θ=5csc4θ−20csc2θ+16, a quadratic in csc2θ (≥1), minimized (via completing the square) at value -4. Answer the question to unlock