Question 287 of 455MediumMCQ
Let p,q∈R. If 2−3 is a root of x2+px+q=0, then: Solutions · 1
Official solution
The conjugate surd root 2+3 must also be a root: x2+px+q=(x−2+3)(x−2−3)=x2−4x+1.
So p=−4, q=1, and p2−4q−12=16−4−12=0. Answer the question to unlock