Question 267 of 455MediumMCQ
Let α and β be two roots of x2+2x+2=0. Then α15+β15 is equal to: Solutions · 1
Official solution
α,β=−1±i=2e±3iπ/4.
\[\alpha^{15}+\beta^{15}=(\sqrt{2})^{15}\left(e^{i45\pi/4}+e^{-i45\pi/4}\right)=(\sqrt{2})^{15}\cdot2\cos\frac{3\pi}4=2(\sqrt{2})^{14}\cdot\left(-\frac1{\sqrt{2}}\right)=-256.\] Answer the question to unlock