Let |z_1-8-2i| 1 and |z_2-2+6i| 2, z_1,z_2 C.

Question

Let $|{z}_{1}-8-2i|\le 1$ and $|{z}_{2}-2+6i|\le 2$, ${z}_{1},{z}_{2}\in C$. Then the minimum value of $|{z}_{1}-{z}_{2}|$ is :

Accepted Answer

$$\begin{aligned}
& \because \mathrm{AB}=\sqrt{100}=10 \
& \therefore\left|\mathrm{Z}_1-\mathrm{Z}_2\right|_{\min }=10-2-1=7
\end{aligned}$$

Solutions · 1