The least positive integer n such that (1−i)n−2(2i)n, i=−1, is a positive integer, is
Answer: 6
Solutions · 1
Official solution
(1−i)n−2(2i)n=(i−1)n(−2i) after simplification. Testing n=1,2,4,6 shows n=1,2,4 give non-real or non-positive values, while n=6 gives −2i(i−1)6=16, a positive integer. Least such n is 6.