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Joint Entrance Examination
Mathematics
Complex Numbers
Question 216
Question 216 of 455
Easy
MCQ
The number of real solutions of the equation
x
2
−
∣
x
∣
−
12
=
0
x^2-|x|-12=0
x
2
−
∣
x
∣
−
12
=
0
is
A
2
B
3
C
1
D
4
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Official solution
∣
x
∣
2
−
∣
x
∣
−
12
=
0
⟹
(
∣
x
∣
−
4
)
(
∣
x
∣
+
3
)
=
0
⟹
∣
x
∣
=
4
|x|^2-|x|-12=0 \implies (|x|-4)(|x|+3)=0 \implies |x|=4
∣
x
∣
2
−
∣
x
∣
−
12
=
0
⟹
(
∣
x
∣
−
4
)
(
∣
x
∣
+
3
)
=
0
⟹
∣
x
∣
=
4
(rejecting
∣
x
∣
=
−
3
|x|=-3
∣
x
∣
=
−
3
). So
x
=
±
4
x=\pm4
x
=
±
4
, giving 2 real solutions.
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