Let C be the set of complex numbers. Let S1={z∈C:∣z−2∣≤1} and S2={z∈C:z(1+i)+zˉ(1−i)≥4}. Then the maximum value of z−252 for z∈S1∩S2 is equal to
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Official solution
S1: disk centred (2,0) radius 1. S2: x−y≥2. Points on the boundary circle: A=(2+cosθ,sinθ), θ∈[−43π,4π].
\[(AP)^2=\left(\cos\theta-\frac12\right)^2+\sin^2\theta=\frac54-\cos\theta,\]
maximized at θ=−43π: (AP)2=45+21=45+22.