Question 199 of 455MediumNUMERICAL
Let z1,z2 be the roots of the equation z2+az+12=0 and z1,z2 form an equilateral triangle with the origin. Then the value of ∣a∣ is
Answer: 6 Solutions · 1
Official solution
z1+z2=−a, z1z2=12. For 0,z1,z2 equilateral: z12+z22=z1z2, so (z1+z2)2=3z1z2⟹a2=3(12)=36⟹∣a∣=6. Answer the question to unlock