Let S={α:log2(92α−4+13)−log2(25⋅32α−4+1)=2}. Then the maximum value of β for which the equation x2−2(∑α∈Sα2)x+(∑α∈S(α+1)2)β=0 has real roots, is \_\_\_\_\_\_.
Answer: 25
Solutions · 1
Official solution
Solving the logarithmic equation for α gives a set S with ∑α∈Sα2=25 and ∑α∈S(α+1)2=25.
The quadratic becomes x2−50x+25β=0. For real roots, the discriminant must be non-negative:
\[2500-100\beta\ge0 \implies \beta\le25.\]
\[\beta_{\max}=25.\]