Let S={z∈C:∣z−1∣=1 and (2−1)(z+zˉ)−i(z−zˉ)=22}. Let z1,z2∈S [be defined by a further geometric condition not fully preserved in the source]. Then [the required quantity] is:
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Official solution
Writing z=x+iy, the second condition becomes the line 2(2−1)x+2y=22, i.e. (2−1)x+y=2. Intersecting this line with the circle ∣z−1∣=1 (centre (1,0), radius 1) determines specific points of S; per the source, z1 is the intersection of the circle with a line L1 through a point P, and z2 is the intersection of lines L1 and L2 (the shaded-region construction). The final computed value is 2.