The area (in square units) of the part of circle x^2+y^2=169 which is below the line 5x-y=…

Question

The area (in square units) of the part of circle $x^2+y^2=169$ which is below the line $5x-y=13$ is $\dfrac{\alpha}{\beta}\pi + (	ext{rational term})$, where $\alpha,\beta$ are coprime. Then $\alpha+\beta$ is equal to \_\_\_\_\_\_\_\_.

Answer: 171

Accepted Answer

*(The precise line equation and resulting circular-segment computation could not be reliably reconstructed from the corrupted source text --- the raw angle does not reduce to a standard value with the equation as transcribed. The stated answer is $171$.)*

Solutions · 1