A square is inscribed in the circle x2 + y2
-- 6x + 8y -- 103 = 0 with its sides parallel to the coordinate axes.
Then the distance of the vertex of this square which is nearest to the origin is :
Solutions · 1
Official solution
R \[ = \sqrt {9 + 16 + 103} = 8\sqrt 2 \]
OA =13
OB \[ = \sqrt {265} \]
OC \[ = \sqrt {137} \]
OD \[ = \sqrt {41} \]