Let C1 and C2 be the centres of the circles x2 + y2 -- 2x -- 2y -- 2 = 0 and x2 + y2 -- 6x…

Question

Let C1 and C2 be the centres of the circles x2  + y2 -- 2x -- 2y -- 2 = 0 and x2 + y2 -- 6x -- 6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2 is :

Accepted Answer

Area  = 2 $$ \times $$ $${1 \over 2}$$.4 = 2

Solutions · 1