If the angle of intersection at a point where the two circles with radii 5 cm and 12 cm intersect is 90o, then
the length (in cm) of their common chord is :
Solutions · 1
Official solution
C1C2 = \[\sqrt {{{12}^2} + {5^2}} \] = 13
Area of \[\Delta \]AC1C2 = \[{1 \over 2}.12.5 = {1 \over 2}.13{{AB} \over 2} \Rightarrow AB = {{120} \over {13}}units\]