The two circles x2+y2=ax and x2+y2=c2(c>0) touch each other if:
Solutions · 1
Official solution
Circle 1: centre (2a,0), radius 2∣a∣. Circle 2: centre (0,0), radius c.
Distance between centres =2∣a∣. Since circle 1 passes through the origin (the centre of circle 2), the circles are internally tangent when
\[\frac{|a|}{2}=\left|c-\frac{|a|}{2}\right|\ \Rightarrow\ c=|a|\ \ (\text{taking the non-trivial branch}).\]