If the angle of intersection at a point where the two circles with radii 5cm and 12cm intersect is 90∘, then the length (in cm) of their common chord is:
Solutions · 1
Official solution
Orthogonal intersection makes △PC1C2 right-angled at P (intersection point), with legs 5,12 and hypotenuse C1C2=13.
The common chord is perpendicular to C1C2; the distance from P to C1C2 (the altitude to the hypotenuse) is 135×12=1360, and this equals half the common chord:
\[\text{Common chord}=2\times\frac{60}{13}=\frac{120}{13}.\]