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Joint Entrance Examination
Mathematics
Circle
Question 107
Question 107 of 219
Medium
MCQ
Consider a circle
C
C
C
which touches the
Y
Y
Y
-axis at
(
0
,
6
)
(0,6)
(
0
,
6
)
and cuts off an intercept
6
5
6\sqrt{5}
6
5
on the
X
X
X
-axis. Then the radius of the circle
C
C
C
is equal to
A
53
\sqrt{53}
53
B
9
9
9
C
8
8
8
D
82
\sqrt{82}
82
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Official solution
\[r = \sqrt {{6^2} + {{\left( {3 + \sqrt 5 } \right)}^2}} \] \[ = \sqrt {36 + 45} = 9\]
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