For the four circles M,N,O and P, the following four equations are given: [M:x^2+y^2=1, N:…

Question

For the four circles $M,N,O$ and $P$, the following four equations are given:
$$M:x^2+y^2=1,\quad N:x^2+y^2-2x=0,\quad O:x^2+y^2-2x-2y+1=0,\quad P:x^2+y^2-2y=0.$$
If the centre of circle $M$ is joined with the centre of $N$, then $N$ to $O$, then $O$ to $P$, and lastly $P$ back to $M$, these lines form the sides of a

Accepted Answer

Centres: $M(0,0)$, $N(1,0)$, $O(1,1)$, $P(0,1)$ --- the unit square.

Solutions · 1