Official solution
\[{T_{r + 1}} = {}^{12}{C_r}{\left( {{2^{1/3}}} \right)^r}.{\left( {{3^{1/4}}} \right)^{12 - 4}}\]
Tr + 1 will be rational number when r = 0, 3, 6, 9, 12 \& r = 0, 4, 8, 12
\[\Rightarrow\] r = 0, 12
T1 + T13 = 1 \[\times\] 33 + 1 \[\times\] 24 \[\times\] 1
= 24 + 16 = 43