If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n and B denotes the sum of all the coefficients in the expansion of (1+x2)n, then :
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Official solution
Sum of coefficients in the expansion of (1−3x+10x2)n=A
then A=(1−3+10)n=8n (put x=1)<?p>
and sum of coefficients in the expansion of
(1+x2)n=BB=(1+1)n=2nA=B3