If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n and B denotes the sum of all the coefficients in the expansion of (1+x2)n, then :
Solutions · 1
Official solution
Sum of coefficients in the expansion of \[\left(1-3 \mathrm{x}+10 \mathrm{x}^2\right)^{\mathrm{n}}=\mathrm{A}\]
then A=(1−3+10)n=8n (put x=1)
and sum of coefficients in the expansion of
\[(1+x2)n=B then B=(1+1)n=2nA=B3\]