Let (x + 10)50 + (x - 10)50 = a0 + a1x + a2x2 + .

Question

Let (x + 10)50 + (x - 10)50 = a0 + a1x + a2x2 + . . . . + a50x50, for all x $$ \in $$ R; then $${{{a_2}} \over {{a_0}}}$$ is equal to

Accepted Answer

(10 + x)50 + (10 - x)50

$$ \Rightarrow $$  a2 = 2.50C2 1048, a0 = 2.1050

$${{{a_2}} \over {{a_0}}} = {{^{50}{C_2}} \over {{{10}^2}}} = 12.25$$

Solutions · 1