The coefficients of xp and xq in the expansion of (1+x)p+q are:
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Official solution
Here in this expansion \[{\left( {1 + x} \right)^{p + q}}\]
The general term = \[{T_{r + 1}} = {}^{p + q}{C_r}.{\left( x \right)^r}\]
\[\therefore\] xp will be present in the term = \[{}^{p + q}{C_p}.{\left( x \right)^p}\]
So coefficient of xp = p+qCp
And xq will be present in the term = \[{}^{p + q}{C_q}.{\left( x \right)^q}\]
\[\therefore\] coefficient of xq = p+qCq
We know nCr = nCn−r
\[\therefore\] p+qCq = \[{}^{p + q}{C_{\left( {p + q} \right) - q}}\] = p+qCp
So coefficients of xp and xq are equal.