If f(y)=1−(y−1)+(y−1)2−(y−1)3+⋯−(y−1)17, then the coefficient of y2 in it is:
Solutions · 1
Official solution
Coefficient of y2 in (y−1)n is nC2(−1)n−2. Summing over n=2 to 17 with alternating signs (matching the given series structure):
\[{}^2C_0+{}^3C_1+{}^4C_2+{}^5C_3+\cdots+{}^{17}C_{15}\]
Using the hockey-stick identity repeatedly, this telescopes to 18C15=18C3.