The coefficient of x2 in the expansion of the product (2−x2)⋅[(1+2x+3x2)6+(1−4x2)6] is:
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Official solution
Let A=(1+2x+3x2)6+(1−4x2)6. Constant term of A: 1+1=2.
Coefficient of x2 in A: from (1+2x+3x2)6: (16)⋅3+(26)⋅22=18+60=78... following the source: coefficient of x2 in (1+2x+3x2)6 is 60+18=78? Let's use the source computation directly: coefficient of x2 in A=54 (from source: 60+6×3−24=54).
\[\text{Coeff. of }x^2\text{ in }(2-x^2)A = 2(54)-1(2)=108-2=106\]