Question 227 of 347MediumMCQ
The value of r for which 20Cr20C0+20Cr−120C1+20Cr−220C2+⋯+20C020Cr is maximum, is: Solutions · 1
Official solution
This sum equals (20C0)2+(20C1)2+⋯ when r=20 (giving ∑(20Ck)2=40C20), which is the maximum possible value of this Vandermonde-type sum.
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