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Question 182 of 347MediumMCQ
Let [x][x] denote the greatest integer ≤x\le x. If for n∈Nn\in N, (1−x+x3)n=∑j=03najxj(1-x+x^3)^n=\displaystyle\sum_{j=0}^{3n}a_jx^j, then ∑j=0⌊3n/2⌋a2j+4∑j=0⌊(3n−1)/2⌋a2j+1\displaystyle\sum_{j=0}^{\lfloor3n/2\rfloor}a_{2j}+4\sum_{j=0}^{\lfloor(3n-1)/2\rfloor}a_{2j+1} is equal to
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