Question 182 of 347MediumMCQ
Let [x] denote the greatest integer ≤x. If for n∈N, (1−x+x3)n=j=0∑3najxj, then j=0∑⌊3n/2⌋a2j+4j=0∑⌊(3n−1)/2⌋a2j+1 is equal to Solutions · 1
Official solution
Putting x=1: (1−1+1)n=1=a0+a1+⋯+a3n ...(i)
Putting x=−1: (1+1−1)n=1=a0−a1+a2−⋯ ...(ii)
Adding: 2=2(a0+a2+a4+⋯)⇒a0+a2+a4+⋯=1
Subtracting: 0=2(a1+a3+⋯)⇒a1+a3+⋯=0
\[\sum a_{2j}+4\sum a_{2j+1} = 1+4(0)=1\] Answer the question to unlock