Question 138 of 347MediumNUMERICAL
Let [t] denote the greatest integer ≤t. If the constant term in the expansion of (3x2−2x51)7 is α, then [α] is equal to \_\_\_\_\_\_\_.
Answer: 1275 Solutions · 1
Official solution
\[T_{r+1}=\binom7r(3x^2)^{7-r}\left(-\frac{1}{2x^5}\right)^r\]
Power: 14−2r−5r=14−7r=0⇒r=2.
\[T_3=\binom72\,3^5\left(\frac12\right)^2=21\times\frac{243}{4}=1275.75\]
\[[\alpha]=1275\] Answer the question to unlock