Question 126 of 347MediumMCQ
The coefficient of x301 in (1+x)500+x(1+x)499+x2(1+x)498+⋯+x500 is: Solutions · 1
Official solution
The coefficient of x301 in
\[{(1 + x)^{500}} + x{(1 + x)^{499}} + {x^2}{(1 + x)^{498}}\, + \,...\, + \,{x^{500}}\]
\[{}^{500}{C_{301}} + {}^{499}{C_{300}} + {}^{498}{C_{299}}\, + \,...\, + \,{}^{199}{C_0}\]
\[ = {}^{500}{C_{199}} + {}^{499}{C_{199}} + {}^{498}{C_{199}}\, + \,...\, + \,{}^{199}{C_{199}}\]
=501C200 Answer the question to unlock