The constant term in the expansion of (2x+x1)7(3x2)? *(five-term multinomial variant)* is \_\_\_\_\_\_.
Answer: 1080
Solutions · 1
Official solution
Using the multinomial general term n1!n2!n3!5!(2x)n1(x−7)n2(3x2)n3 with n1+n2+n3=5; for the constant term, n1+2n3=7n2 and n1+n2+n3=5. The only solution is n1=1,n2=1,n3=3.
\[\text{Constant term}=\frac{5!}{1!1!3!}(2)^1(3)^3=20\times2\times27=1080\]