If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n and B denotes the sum of all the coefficients in the expansion of (1+x2)n, then:
Solutions · 1
Official solution
Sum of all coefficients is obtained by putting x=1.
A=(1−3+10)n=8nB=(1+1)n=2n
So A=8n=(2n)3=B3.