Question 10 of 347MediumMCQ
The sum of all possible values of n∈N, so that the coefficients of x,x2 and x3 in the expansion of (1+x2)2(1+x)n, are in arithmetic progression is : Solutions · 1
Official solution
(1+x2)2(1+xn)(1+x4+2x2)(1+x)nx=nC1x2=nC2+2⋅nC0x3=nC3+2⋅nC1∵x,x2,x3→AP⇒2(nC2+2)=nC1+nC3+2n2nC2+4=nC3+3n⇒n2−9n2+26n−24=0⇒n=2,3,4⇒n9 Answer the question to unlock