The area bounded by the curves y=lnx, y=ln∣x∣, y=∣lnx∣ and y=∣ln∣x∣∣ is:
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Official solution
The graph of y=∣f(x)∣ is obtained by reflecting, above the x-axis, the portion of y=f(x) that lies below it. Combining the four curves and using symmetry about both axes:
\[\text{Area} = 4\int_0^1(-\ln x)\,dx = -4\left[x\ln x - x\right]_0^1 = -4(0-1) = 4 \text{ sq. units}\]