The area of the region bounded by the curve y=x^3 and the lines y=8, x=0, is:

Question

The area of the region bounded by the curve $y=x^3$ and the lines $y=8$, $x=0$, is:

Accepted Answer

$$\text{Area} = \int_0^8 y^{1/3}\,dy = \left[\frac34y^{4/3}\right]_0^8 = \frac34\times16 = 12$$

Solutions · 1