The area (in sq. units) of the region {(x,y):y2≥2x and x2+y2≤4x,x≥0,y≥0} is:
Solutions · 1
Official solution
Points of intersection of the two curves are \[\left( {0,0} \right),\left( {2,2} \right)\] and \[\left( {2, - 2} \right)\]
Area = Area (OAB)− area under parabola (0 to 2 )
\[ = {{\pi \times {{\left( 2 \right)}^2}} \over 4} - \int\limits_0^2 {\sqrt 2 \sqrt x } \,dx\]
\[ = \pi - {8 \over 3}\]