The area (in sq.

Question

The area (in sq. units) of the region bounded by the curve $x^2=4y$ and the straight line $x=4y-2$ is:

Accepted Answer

x = 4y - 2 \& x2 = 4y

$$ \Rightarrow $$  x2 = x + 2 $$ \Rightarrow $$ x2 - x - 2 = 0

x = 2, - 1

So,   $$\int\limits_{ - 1}^2 {\left( {{{x + 2} \over 4} - {{{x^2}} \over 4}} \right)\,dx = {9 \over 8}} $$

Solutions · 1