The area (in sq. units) of the region A={(x,y):∣x∣+∣y∣≤1,2y2≥∣x∣} is:
Solutions · 1
Official solution
By symmetry, work in the region x≥0, y≥0 and multiply appropriately. The boundary curves y=1−x (from ∣x∣+∣y∣=1) and 2y2=x meet where 2y2=1−y⇒2y2+y−1=0⇒y=21.
Using symmetry (four congruent lobes by reflection):
\[\text{Area} = 4\int_0^{1/2}2y^2\,dy + \frac12\cdot\text{Area}(\triangle PAB) = \frac56\]
(triangle correction term as in the source's decomposition of the diamond minus the parabolic cut-outs) gives the final area 65.