Question 117 of 230MediumMCQ
The area (in sq. units) of the region A={(x,y):(x−1)[x]≤y≤2x, 0≤x≤2}, where [t] denotes the greatest integer function, is: Solutions · 1
Official solution
y = (x -- 1)[x] = \[\left\{ {0,x−1,2,0≤x<11≤x<2x=2 } \right.\]
A = \[\int\limits_0^2 {2\sqrt x } dx - {1 \over 2}.1.1\]
= 2\[\left[ {{{{x^{3/2}}} \over {{3 \over 2}}}} \right]_0^2\] - \[{1 \over 2}\]
= \[{{8\sqrt 2 } \over 3} - {1 \over 2}\] Answer the question to unlock