Official solution
\[{y^2} = 18x \Rightarrow 2y{{dy} \over {dx}} = 18 \Rightarrow {{dy} \over {dx}} = {9 \over y}\]
Given \[{{dy} \over {dx}} = 2 \Rightarrow {9 \over 2} = 2 \Rightarrow y = {9 \over 2}\]
Puting in \[{y^2} = 18x \Rightarrow x = {9 \over 8}\]
\[\therefore\] Required point is \[\left( {{9 \over 8},{9 \over 2}} \right)\]