Let [f: R (0, )] be strictly increasing function such that [ _x (f(7 x))/(f(x))=1].

Question

Let $$f: \rightarrow \mathbb{R} \rightarrow(0, \infty)$$ be strictly increasing function such that $$\lim _\limits{x \rightarrow \infty} \frac{f(7 x)}{f(x)}=1$$. Then, the value of $$\lim _\limits{x \rightarrow \infty}\left[\frac{f(5 x)}{f(x)}-1\right]$$ is equal to

Accepted Answer

$$\begin{aligned}
& f: R \rightarrow(0, \infty) \
& \lim _{x \rightarrow \infty} \frac{f(7 x)}{f(x)}=1
\end{aligned}$$

$$\because \mathrm{f}$$

Solutions · 1