Official solution
V = l . b . h = (a - 2x)(b - 2x) x
\[\Rightarrow\] V(x) = (2x - a)(2x - b) x
\[\Rightarrow\] V(x) = 4x3 - 2(a + b)x2 + abx
\[ \Rightarrow {d \over {dx}}v(x) = 12{x^2} - 4(a + b)x + ab\]
\[{d \over {dx}}(v(x)) = 0 \Rightarrow 12{x^2} - 4(a + b)x + ab = 0 < _\beta ^\alpha \]
\[ \Rightarrow x = {{4(a + b) \pm \sqrt {16{{(a + b)}^2} - 48ab} } \over {2(12)}}\]
\[ = {{(a + b) \pm \sqrt {{a^2} + {b^2} - ab} } \over 6}\]
Let \[x = \alpha = {{(a + b) + \sqrt {{a^2} + {b^2} - ab} } \over 6}\]
\[\beta = {{(a + b) - \sqrt {{a^2} + {b^2} - ab} } \over 6}\]
Now, \[12(x - \alpha )(x - \beta ) = 0\]
\[\therefore\] x = \[\beta\] \[ = {{a + b - \sqrt {{a^2} + {b^2} - ab} } \over b}\]