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Joint Entrance Examination
Mathematics
Application of Derivatives
Question 14
Question 14 of 212
Medium
MCQ
The sum of all local minimum values of the function
f
(
x
)
=
1
−
2
x
,
x
2
f(x)=\begin{array}{|cc|}1-2x, & x2\end{array}
f
(
x
)
=
1
−
2
x
,
x
2
is
A
167
72
\frac{167}{72}
72
167
B
157
72
\frac{157}{72}
72
157
C
171
72
\frac{171}{72}
72
171
D
131
72
\frac{131}{72}
72
131
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Official solution
f(x)=\begin{gathered} 1-2x, x2
\therefore AB \\ \frac{7}{3}-\frac{11}{72} \\ \Rightarrow \frac{168-11}{72}\Rightarrow \frac{157}{72} \end{gathered}
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