The tangent to the curve y = x2 -- 5x + 5, parallel to the line 2y = 4x + 1, also passes t…

Question

The tangent to the curve y = x2 -- 5x + 5, parallel to the line 2y = 4x + 1, also passes through the point :

Accepted Answer

y = x2 - 5x + 5

$${{dy} \over {dx}} = 2x - 5 = 2 \Rightarrow x = {7 \over 2}$$

at  x = $${7 \over 2}$$, y = $${{ - 1} \over 4}$$

Equation of tangent at

$$\left( {{7 \over 2},{{ - 1} \over 4}} \right)$$ is 2x - y - $${{29} \over 4}$$ = 0

Now check options

x = $${1 \over 8}$$, y = -7

Solutions · 1