A plane which passes through the point (3,2,0) and the line x-41=y-75=z-44 is

Question

A plane which passes through the point $(3,2,0)$ and the line $\dfrac{x-4}1=\dfrac{y-7}5=\dfrac{z-4}4$ is

Accepted Answer

The line passes through $(4,7,4)$, so the required plane must contain both $(3,2,0)$ and $(4,7,4)$. Testing option A: $3-2+0=1$  and $4-7+4=1$  --- both points satisfy $x-y+z=1$, confirming it as the required plane.

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