Question 445 of 521MediumMCQ
The intersection of the spheres x2+y2+z2+7x−2y−z=13 and x2+y2+z2−3x+3y+4z=8 is the same as the intersection of one of the spheres and the plane Solutions · 1
Official solution
The equation of spheres are
\[{S_1}:{x^2} + {y^2} + {z^2} + 7x - 2y - z - 13 = 0\] and
\[{S_2}:{x^2} + {y^2} + {z^2} - 3x + 3y + 4z - 8 = 0\]
Their plane of intersection is S1−S2=0
\[ \Rightarrow 10x - 5y - 5z - 5 = 0\]
\[ \Rightarrow 2x - y - z = 1\] Answer the question to unlock