A line with positive direction cosines passes through the point P(2,−1,2) and makes equal angles with the coordinate axes. If the line meets the plane 2x+y+z=9 at point Q, then the length PQ equals
Solutions · 1
Official solution
Equal direction cosines ⇒ equal direction ratios: point on line (h,h−3,h) (since y=h−3 keeps ratios equal to the x,z increments from P). Substituting into the plane: 2h+(h−3)+h=9⇒4h=12⇒h=3, giving Q=(3,0,3).
\[PQ=\sqrt{(3-2)^2+(0+1)^2+(3-2)^2}=\sqrt{3}.\]